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Byju's Answer
Standard XII
Mathematics
Focii of Hyperbola
Trace the par...
Question
Trace the parabolas :
16
x
2
−
24
x
y
+
9
y
2
+
32
x
+
856
y
−
39
=
0
.
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Solution
Trace the equation
16
x
2
−
24
x
y
+
9
y
2
+
32
x
+
856
y
−
39
=
0
4
x
−
3
y
+
4
=
±
√
55
−
880
y
(
4
x
−
3
y
+
4
)
2
=
55
−
880
y
=
−
880
[
y
−
1
160
]
Let
4
x
−
3
y
+
4
=
Y
y
−
1
160
=
X
Y
2
=
−
880
X
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