wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Train A leaves Ludhiana for Delhi at 11 am running at a speed of 60 km/hr. Train B leaves Ludhiana for Delhi by the same route at 2 pm on the same day, running at a speed of 72 km/hr. At what time will the two trains meet each other ?

A
5 am on the next day
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2 am on the next day
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5 pm on the next day
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2 pm on the next day
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5 am on the next day
Distance covered by train A before train B leaves Ludhiana = 60×3=180 km Relative speed = (7260) km/hr = 12 km/hr
Time taken to cross each other = 18012 hrs = 15 hrs
Required time = 2 pm + 15 hrs = 5 am on the next day

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Direct Proportions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon