Question

Trajectory of a projectile is $y=Ax-B{x}^2$. It's horizontal range is:

• A. $AB$
• B. $\frac{A}{B}$
• C. $\frac{B}{A}$
• D. $A^2+B^2$

Answer 1

Answer: (B)

$\frac{A}{B}$

$y=Ax-B{x}^2$
Horizontal range is when $y=0,$
$0=Ax-B{x}^2$
$x=0,\frac{A}{B}$
Clearly, horizontal range is $\frac{A}{B}$.