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Direction of Angular Velocity

Trajectory of...

Question

Trajectory of a projectile near the surface of Earth is $y = 4 x - 12 x^{2}$ . If $y$ is vertical axis and $x$ is horizontal then angle of projection is

A

t a n^{- 1} (1)

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B

t a n^{- 1} (4)

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C

t a n^{- 1} (\sqrt{3})

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D

t a n^{- 1} (\sqrt{2})

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Solution

The correct option is B $t a n^{- 1} (4)$
We know that the path of a projectile is given by,
$y = t a n θ x - \frac{g}{2 u^{2} c o s^{2} θ} x^{2}$
Coefficient of $x = t a n θ = 4$
$θ = t a n^{- 1} (4)$

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