Transition metals have the general electronic configuration?

n s^{2} n d^{1 - 10}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n s^{2} n p^{1} (n - 1) d^{1 - 10}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n s^{1 - 2} (n - 1) d^{1 - 10}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

n s^{2} n p^{6} (n - 1) d^{1 - 10}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $n s^{1 - 2} (n - 1) d^{1 - 10}$
Electronic configuration of transition metal is:
$\Rightarrow$ [Nobel gas] $n s^{1 - 2} (n - 1) d^{1 - 10}$
For example- Chromium has $[A r] 4 s^{1} 3 d^{5}$

Suggest Corrections

Similar questions

The outer electron configuration of first transition series is ${(n - 1) d}^{1 - 10} {n s}^{1 - 2}$ . Then value of $n$ is:

(n - 1) d^{1 - 10} n s^{1 - 2}

(n - 1) d^{1 - 10} n s^{1 - 2}

d -

(n - 1) d^{1 - 10} n s^{1 - 2}

n s^{2} (n - 1) d^{1 - 10} (n - 2) f^{1 - 14}

Join BYJU'S Learning Program