Question

Translate the following statements into chemical equations and balance them. Hydrogen sulfide gas burns in air to give water and sulfur dioxide.

Answer 1

Balanced chemical equation

• Chemical reactions, in which reactants combine to form products, are represented by chemical equations.
• Stoichiometric coefficients are added to the reactants and products to balance chemical equations.
• It's significant because the principles of mass conservation and constant proportions require a chemical equation to be applied.
• When the law of conservation of mass is applied to a chemical, neither an atom is generated nor destroyed on either side of the reaction, resulting in an equal number of elements in both the reactant and the product.

Chemical reaction

• Burning hydrogen sulfide gas $\left({\mathrm{H}}_2\mathrm{S}\right)$ in air produces Sulfur dioxide $\left({\mathrm{SO}}_2\right)$ and water $\left({\mathrm{H}}_2\mathrm{O}\right)$.
• The chemical equation is as follows:

${\mathrm{H}}_2\mathrm{S}\left(\mathrm{g}\right)+{\mathrm{O}}_2\left(\mathrm{g}\right)\to {\mathrm{SO}}_2\left(\mathrm{g}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

Balancing the chemical equation

• The number of Hydrogen $\left(\mathrm{H}\right)$, Sulfur $\left(\mathrm{S}\right)$ atoms are equal on both sides but, Oxygen $\left(\mathrm{O}\right)$ atom on both sides are not equal.
• Add $3$ to oxygen on the reactant side.
• Add $2$ before ${\mathrm{H}}_2\mathrm{O}$ and ${\mathrm{SO}}_2$ on the product side.
• Add $2$ in front of ${\mathrm{H}}_2\mathrm{S}$ on the reactant side.
• The balanced equation is as follows:

$2{\mathrm{H}}_2\mathrm{S}\left(\mathrm{g}\right)+3{\mathrm{O}}_2\left(\mathrm{g}\right)\to 2{\mathrm{SO}}_2\left(\mathrm{g}\right)+2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$