Question

Translate the given statement into a chemical equation and then balance it.​

Barium chloride reacts with aluminium sulphate to give ​aluminium chloride and a precipitate of barium sulphate

Answer 1

Step 1: Translating the given equation into a skeletal equation:
${\mathrm{BaCl}}_2+{\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3\to {\mathrm{BaSO}}_4+{\mathrm{AlCl}}_3$

Step 2: Balancing S atoms:
$\mathrm{Place}3\mathrm{as}a\mathrm{coefficient}\mathrm{before}{\mathrm{BaSO}}_4$
${\mathrm{BaCl}}_2+{\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3\to 3{\mathrm{BaSO}}_4+{\mathrm{AlCl}}_3$

Step 3: Balancing Ba atoms:
$\mathrm{Place}3\mathrm{as}a\mathrm{coefficient}\mathrm{before}{\mathrm{BaCl}}_2$
$3{\mathrm{BaCl}}_2+{\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3\to 3{\mathrm{BaSO}}_4+{\mathrm{AlCl}}_3$

Step 4: Balancing Al atoms:
$\mathrm{Place}2\mathrm{as}\mathrm{coefficient}\mathrm{before}{\mathrm{AlCl}}_3$
$3{\mathrm{BaCl}}_2+{\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3\to 3{\mathrm{BaSO}}_4+2{\mathrm{AlCl}}_3$

The chemical equation is now balanced.