Translate the triangle 4 units’ right and 3 units down. What are the coordinates of the image?
Translate the triangle 4 units’ right and 3 units down. What are the coordinates of the image?
We know that to translate a figure ‘a’ units horizontally and ‘b’ units vertically in the coordinate plane, ‘a’ is to be added to the
x-coordinate and ‘b’ is to be added to the y-coordinates of the vertices. Then new coordinates become:-
A (x,y) = A'(x+a, y+b)
The value ‘a’ and ‘b’ will be positive if the shift is Right and Vertical up respectively and the value of ‘a’ and ‘b’ will be negative if the shift is left and vertical down respectively.
Now we have the given points from graph: J(-1,3), K(-1,1), L(-4,1)
and
a = 4, b = -3
Then the new coordinates will become:-
J'(-1 + a, 3 + b) = J'(-1+4,3-3) = J'(3,0)
K'(-1 + a, 1 + b) = K'(-1 + 4, 1 – 3) = K'(3,-2)
L'(-4 + a, 1 + b) = L'(-4 + 4, 1 – 3) = L'(0,-2)
Hence the coordinate of image is J'(3,0), K'(3,-2), L'(0,-2)
Final Answer: The coordinate of image is J'(3,0), K'(3,-2), L'(0,-2)
We know that to translate a figure ‘a’ units horizontally and ‘b’ units vertically in the coordinate plane, ‘a’ is to be added to the
x-coordinate and ‘b’ is to be added to the y-coordinates of the vertices. Then new coordinates become:-
A (x,y) = A'(x+a, y+b)
The value ‘a’ and ‘b’ will be positive if the shift is Right and Vertical up respectively and the value of ‘a’ and ‘b’ will be negative if the shift is left and vertical down respectively.
Now we have the given points from graph: J(-1,3), K(-1,1), L(-4,1)
and
a = 4, b = -3
Then the new coordinates will become:-
J'(-1 + a, 3 + b) = J'(-1+4,3-3) = J'(3,0)
K'(-1 + a, 1 + b) = K'(-1 + 4, 1 – 3) = K'(3,-2)
L'(-4 + a, 1 + b) = L'(-4 + 4, 1 – 3) = L'(0,-2)
Hence the coordinate of image is J'(3,0), K'(3,-2), L'(0,-2)
Final Answer: The coordinate of image is J'(3,0), K'(3,-2), L'(0,-2)
