Treatment of conc. $H I$ with ethyl ether will give the product:

C_{2} H_{5} O H

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C_{2} H_{5} I

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Both the above

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None of the above

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Solution

The correct option is C Both the above
Reaction:
$C_{2} H_{5} O C_{2} H_{5} + H I \to C_{2} H_{5} O H + C_{2} H_{5} I$
Option A and B are correct.

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Similar questions

N a / C_{2} H_{5} O H

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A

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C_{2} H_{5} O H

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