Question

Trial slip circle on a finite slope of clayey soil (c = $20kN/m^2,\varphi =0$) is shown in the figure.


The factor of safety against sliding is ?.
(Rounded upto two decimal places)

• A. 1.396
• B. 2.465
• C. 0.847
• D. 3.245

Answer 1

The correct option is A 1.396



$Resistingmoment{M}_R=(c\times \stackrel{⌢}{AB})r$

$=c\times 2\pi \times r^2\times \frac{{50}^{\circ }}{{360}^{\circ }}$

$=20\times 2\pi \times 8^2\times \frac{{50}^{\circ }}{{360}^{\circ }}$

$=1117.01kN-m$

$Disturbingmoment\left(M_D\right)=W\times \stackrel{-}{x}$

$=400kN\times 2m$

$=800kNm$

$FOS=\frac{M_R}{M_D}=\frac{1117.01}{800}=1.396$