Triangles on the Same Base and between the Same Parallels
ABC and BDE ...
Question
(△ABCand△BDE) are two equilateral traingles such that D is the midpoint of BC.Then,ar(△BDE):ar(△ABC)=?
(a) 1:2
(b) 1:4
(c) √3:2
(d) 3:4
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Solution
NSWER: (b) 1:4 ∆ ABC and ∆ BDE are two equilateral triangles and D is the midpoint of BC. Let AB = BC = AC = a Then BD = BE = ED = a/2 ∴ ar(∆BDE)ar(∆ABC)= 14 So, required ratio = 1 : 4