△ABC is a right angled triangle. O is the circumcenter of the △ABC and R1,R2,R3 are the radii of the circumcircles of the triangle OBA,OCA and OAB respectively, then aR1+bR2+cR3 is equal to
A
abcR
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B
abcR3
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C
abcR4
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D
None of these
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Solution
The correct option is AabcR3 R1=BC2sin(∠BOC)=a2sin2A⇒aR1=2sin2A