Triangle ABC is an isosceles triangle with AB = AC. The angle opposite BC is 40 degree. What is the measure of the angle opposite to the side AC (in degrees)?

140

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120

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Solution

The correct option is D 70
$∠ A = 40^{\circ}$ [Given]
Since the given triangle is isosceles, the remaining angle will be equal in measure.
Sum of the remaining two angles = 180 - 40 = $140^{\circ}$
$∠ B = ∠ C = \frac{1}{2} \times 140^{\circ} = 70^{\circ}$

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Triangle ABC is an isosceles triangle with AB = AC. The angle opposite BC is 40 degree. What is the measure of the angle opposite to the side AC (in degrees)?

The correct option is D 70∠A=40∘ [Given] Since the given triangle is isosceles, the remaining angle will be equal in measure. Sum of the remaining two angles = 180 - 40 = 140∘ ∠B=∠C=12×140∘=70∘

The correct option is D 70
$∠ A = 40^{\circ}$ [Given]
Since the given triangle is isosceles, the remaining angle will be equal in measure.
Sum of the remaining two angles = 180 - 40 = $140^{\circ}$
$∠ B = ∠ C = \frac{1}{2} \times 140^{\circ} = 70^{\circ}$