Question

$△ABC$ is an isosceles triangle with $AB=AC$. Then the line of symmetry for the $△ABC$ will be:

• A. Perpendicular bisector of $BC$
• B. Angle bisector of $\angle B$
• C. Altitude from vertex $A$ on line $BC$
• D. Median from vertex $C$ to side $AB$

Answer 1

Answer: (A), (C)

The correct options are
A Perpendicular bisector of $BC$
C Altitude from vertex $A$ on line $BC$

Given $AB=AC$

The figure is shown in figure

LINE OF SYMMETRY --

A line of symmetry is a line that divides a figure into two corresponding parts, each of which is the mirror image of the other.

From the above concept , if we draw the perpendicular from $A$ to the $BC$, $BC$ will divide into 2 equal parts because $\Delta ABC$ is isosceles triangle .

Hence $\angle A$ will also divide into 2 equal angle.

The line $BD$ is know as perpendicular bisector of$BC$ and altitude from the $A$ on the $BC$.