You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Perpendicular from Right Angle to Hypotenuse Divides the Triangle into Two Similar Triangles

ABC is right ...

Question

$△$ ABC is right angled at B and the perpendicular drawn to the opposite side bisects it at D. BD =___ cm if AD = DC = 5 cm.

Open in App

Solution

Since $△$ ABC is right angled triangle at B and BD is the perpendicular drawn to the opposite side,
${B D}^{2} = A D \times D C$
$⟹ {B D}^{2} = 5 \times 5$
$B D = \sqrt{25} = 5 cm$

Suggest Corrections

Similar questions

△

ABC is right angled at B and the perpendicular drawn to the opposite side bisects it at D. BD = ___ cm if AD = DC = 5 cm.

$△$ ABC is right angled at B and the perpendicular drawn to the opposite side bisects it at D. if $A D = D C = 5 c m, B D =$ ___ $c m$

$△$ ABC is right angled at B, perpendicular drawn to the opposite side AC bisects AC at D. BD = ___ cm if AD = DC = 5 cm.

$△$ ABC is a right angled triangle, right angled at B and the perpendicular drawn from B to the opposite side bisects it at D. BD = ___ cm, if AD = DC = 5 cm.

△

ABC is right angled at B and the perpendicular drawn to the opposite side bisects it at D. If AD = DC = 5 cm, then BD = .

Join BYJU'S Learning Program

△ ABC is right angled at B and the perpendicular drawn to the opposite side bisects it at D. BD =___ cm if AD = DC = 5 cm.

Since △ ABC is right angled triangle at B and BD is the perpendicular drawn to the opposite side, BD2=AD×DC ⟹BD2=5×5 BD=√25=5 cm

$△$ ABC is right angled at B and the perpendicular drawn to the opposite side bisects it at D. BD =___ cm if AD = DC = 5 cm.

Since $△$ ABC is right angled triangle at B and BD is the perpendicular drawn to the opposite side,
${B D}^{2} = A D \times D C$
$⟹ {B D}^{2} = 5 \times 5$
$B D = \sqrt{25} = 5 cm$