$△$ ABC is right angled at B, perpendicular drawn to the opposite side AC bisects AC at D. BD = ___ cm if AD = DC = 5 cm.

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Solution

Since $△$ ABC is right angled triangle at B and BD is the perpendicular drawn to the opposite side,
${B D}^{2} = A D \times D C$
$⟹ {B D}^{2} = 5 \times 5$
$B D = \sqrt{25} = 5 cm$

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