Question

Triangle ABC is right -angled at C. Find $AC,$ If $AB=2.2cm$and$BC=1.8cm$.
In each case, answer correct to two place of decimal.

• A. $\sqrt{1.6}cm=1.17cm$
• B. $\sqrt{1.6}cm=1.26cm$
• C. $\sqrt{1.6}cm=1.33cm$
• D. $\sqrt{1.6}cm=1.50cm$

Answer 1

Answer: (B)

$\sqrt{1.6}cm=1.26cm$

ABC is right angled at C.

$\therefore A{B}^2=B{C}^2+A{C}^2$

Let's put the given values,

$(2.2{)}^2=(1.8{)}^2+A{C}^2$

$4.84=3.24+A{C}^2$

$AC=\sqrt{1.6}=1.26cm$