Question

$△ABC$ is right angled in which $\angle A={90}^o$ and $AB=AC$. Find $\angle B$ and $\angle C$.

Answer 1

As $AB=AC$, it is an isoceles triangle and the base angles are also same.
$\therefore \angle B=\angle C$
In a triangle, $\angle A+\angle B+\angle C={180}^o$
${90}^o+2\angle B={180}^o⟹2\angle B={180}^o-{90}^o={90}^o$
$\therefore \angle B={45}^o$
$\therefore \angle C={45}^o$