Triangle ABC is similar to triangle PQR. If bisector of angle BAC meets BC at point D and bisector of angkle QPR meets QR at point M, hence, ABPQ=ADPM. If the above statement is true then mention answer as 1, else mention 0 if false
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Solution
Given: △ABC∼△PQR ∠ABC=∠PQR (Corresponding angles) (I) ∠BAC=∠QPR (Corresponding angles) 12∠BAC=12∠QPR (II) Now, AD and PM are angle bisectores of ∠BAC and ∠QPR respectively, thus, in △ABD and △PQM ∠ABD=∠PQM (From I) ∠BAD=∠QPM (From II) ∠BDA=∠QMP (Third angle) Thus, △ABD∼△PQM (AAA rule) Hence, ABPQ=ADPM