△ ABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. △ DEF is similar to △ABC. If EF = 4 cm, then the perimeter of △DEF is -
15 cm
ABDE =ACDF = BCEF = 24 = 12
According to question, DE = 6 cm, AB = 3 cm and DF = 5 cm
∴ Perimeter of △DEF = (DE + EF + DF) = ( 6 + 4 + 5) = 15 cm.