Question

$△$ ABC, right angled at B, $\angle$ACB = ${60}^{\circ }$, expressions for sec 60 and cosec 60 is

• A. AC/BC , AC/AB
• B. AC/BC , AC/BC
• C. AC/AB , AC/AB
• D. AC/AB , AC/BC

Answer 1

The correct option is A

AC/BC , AC/AB

Sec C = $\frac{AC}{BC}$ and cosec C = $\frac{AC}{AB}$ .Since $\angle$ACB =${60}^{\circ }$ .sec 60 = $\frac{AC}{BC}$ and cosec 60 = $\frac{AC}{AB}$