Triangle ABD ~triangle CAD then prove that ad2=bd*cd

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Solution

Above answer is correct if this is not given then assume this...simple we have to proove this so we can assume any two triangle hope u like it.

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Similar questions

In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is false?
a) $△ A B D ≅ △ A C D$ by SAS postulate
b) $△ A B D ≅ △ A C D$ by AAS postulate
c)AB = AC
d)BD = CD

In the given figure, if $∠ B A D = ∠ C A D, ∠ A B D = ∠ A C D,$ then which of the following is false?

Q. In this triangle

A D^{2} = B D \times C D

On the sides AB and AC of triangle ABC, equilateral triangles ABD and ACE are drawn.

Prove that: (i) $∠$ CAD = $∠$ BAE

(ii) CD = BE.

In the following figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that

(i) AB² = BC × BD

(ii) AC² = BC × DC

(iii) AD² = BD × CD

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