Question

$△AMT\sim △AHE.In△AMT,AM=6.3cm,\angle TAM={50}^0,AT=5.6cm,\frac{AM}{AH}=\frac{7}{5}.Construct△AHE.$

Answer 1

Steps of Construction:

Step 1: Draw $△AMT$ such that $AM=6.3cm,\angle TAM={50}^o,AT=5.6cm.$

Step 2: Divide segment $AM$ into $7$ equal parts.

Step 3: Name the end point of the $5th$ part of segment $AM$ as $H$.

Step 4:Draw a line parallel to side $TM$, through $H$. Name the point where the parallel line intersect $AT$ as $E$.

Here, $△AMT\sim △AHE$.