△PQR, right-angled at Q, if PR = 24 cm, QR = 12 cm, then find the value of ∠QRP.
60o
Given: PQR is aright angled triangle, right angled at Q and PR = 24 cm, QR = 12 cm.
In △PQR,
sinP=QRPR=1224
Since, sin30o=0.5
We have ∠RPQ=30o
For a triangle, sum of all the angles =180o
⇒∠PQR+∠QRP+∠RPQ=180o
⇒90o+∠QRP+30o=180o
⇒∠QRP=180o−120o=60o
⇒∠QRP=60o
Hence the correct answer is option B.