Triangle XYZ is right -angled at Z. Calculate the length of YZ, if :

$X Y = 2 \cdot 5 c m a n d X Z = 1 \cdot 5 c m$

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Solution

$∠ X Z Y = 90^{\circ}$
$X Y^{2} = X Z^{2} + Y Z^{2}$ (Using Pythagoras Theorem)
$(2.5)^{2} = (1.5)^{2} + Y Z^{2}$
$Y Z^{2} = 6.25 - 1.25$
$Y Z = 2 c m$

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