TriangleABC is right angle at B if AB=7 cm and AC-BC=1 cm find sinA , cos C

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Solution

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$G i v e n : A B = 7 c m a n d A C - B C = 1 c m \Rightarrow A C = (B C + 1) c m I n r i g h t △ A B C, A C^{2} = A B^{2} + B C^{2} {(B C + 1)}^{2} = 7^{2} + B C^{2} B C^{2} + 1 + 2 B C = 49 + B C^{2} 2 B C = 48 B C = 24 c m S o, A C = 25 c m N o w, \sin A = \frac{B C}{A C} = \frac{24}{25} a n d \cos C = \frac{B C}{A C} = \frac{24}{25}$
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