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Question

Trigonometric functions of (90o+θ) and (180θ) and (180+θ)

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Solution

(90+θ)
sin(90+θ)=cosθ
cos(90+θ)=sinθ
tan(90+θ)=cotθ
cosec(90+θ)=secθ
sec(90+θ)=cosec θ
cot(90+θ)=tanθ

(180θ)
sin(180θ)=sinθ
cos(180θ)=cosθ
tan(180θ)=tanθ
cosec (180θ)=cosec θ
sec(180θ)=secθ
cot(180θ)=cotθ

(180+θ)
sin(180+θ)=sinθ
cos(180+θ)=cosθ
tan(180+θ)=tanθ
cosec (180+θ)=cosec θ
sec(180+θ)=secθ
cot(180+θ)=cotθ

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