Trigonometric ratios of particular ratios:
Ratios / Measures of angles $0^{o}$ $30^{o}$ $45^{o}$ $60^{o}$ $90^{o}$
$sin$ $0$ $\frac{1}{2}$ $\frac{1}{\sqrt{2}}$
$1$
$cos$ $1$ $\frac{\sqrt{3}}{2}$
$\frac{1}{2}$
$tan$ $0$ $\frac{1}{\sqrt{3}}$ $1$ $\sqrt{3}$

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Solution

$s i n 60^{o} = 0.866$
$c o s 45^{o} = 0.707$
$c o s 90^{o} = 0$
$t a n 90^{o} = \infty$

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Similar questions

0^{o}

90^{o}

\frac{1}{2}

How many of the following trigonometric ratios are correct?

(1)Sin ( $15^{\circ}$ ) = $\frac{\sqrt{3} + 1}{2 \sqrt{2}}$

(2)Cos ( $105^{\circ}$ ) = $\frac{1 - \sqrt{3}}{2 \sqrt{2}}$

(3)Sin $75^{\circ}$ = $\frac{\sqrt{3} - 1}{2 \sqrt{2}}$

(4)Tan $15^{\circ}$ = $2 - \sqrt{3}$

\frac{1 + {tan}^{2} 30^{o}}{1 - {tan}^{2} 30^{o}} + {csc}^{2} 60^{0} - {cos}^{2} 45^{o} + {sin}^{2} 45^{o} + \frac{1 + {cot}^{2} 60^{o}}{1 - {cot}^{2} 60^{o}}

cos 2 x + (1 - \sqrt{3}) = (2 - \sqrt{3}) cos x

sin 3 x = 2 sin x,

\sqrt{3} tan x - 1 \geq 0

[0, 5 π]

cos 2 x + (1 - \sqrt{3}) = (2 - \sqrt{3}) cos x

sin 3 x = 2 sin x

\sqrt{3} tan x - 1 \geq 0

[0, 5 π]

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