Trimethylamine is a pyramidal molecule and formamide is a planar molecule. Hybridisation of nitrogen in both is:

s p^{2}, s p^{2}

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s p^{3}, s p^{2}

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s p^{3}, s p^{3}

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s p^{2}, s p

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Solution

The correct option is D $s p^{3}, s p^{2}$
Hence, option $B$ is correct.

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C 3 - C 4

N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

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