Trioxalato aluminate ( III ) and tetrafluoro $-$ borate ( III ) ions are respectively :

[A l {(C_{2} O_{4})}_{3}], {[B F_{4}]}_{4}^{3 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{[A l {(C_{2} O_{4})}_{3}]}_{3}^{3 +}, {[B F_{4}]}_{4}^{3 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{[A l {(C_{2} O_{4})}_{3}]}_{3}^{3 -}, {[B F_{4}]}_{4}^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{[A l {(C_{2} O_{4})}_{3}]}_{3}^{2 -}, {[B F_{4}]}_{4}^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C ${[A l {(C_{2} O_{4})}_{3}]}_{3}^{3 -}, {[B F_{4}]}_{4}^{-}$
Trioxalato aluminate ( III ): A compound with three oxalate ion and Al in +3 oxidation state, so it will have charge of -3. ${[A l {(C_{2} O_{4})}_{3}]}_{3}^{3 -}$ .
Tetrafluoro borate ( III ): Boron in +3 oxidation state and connected with 4 fluoride ions, so it have -1 charge.
${[B F_{4}]}_{4}^{-}$

Suggest Corrections

Similar questions

[A l (C_{2} O_{4})_{3}]^{3 -}

K_{3} [A l {(C_{2} O_{4})}_{3}]

K_{3} [A l (C_{2} O_{4})_{3}]

{sin}^{- 1} a + {sin}^{- 1} b + {sin}^{- 1} c = \frac{3 π}{2}

f (2) = 2, f (x + y) = f (x) f (y) \forall x, y ϵ R

a^{f (2)} + b^{f (4)} + c^{f (6)} - \frac{3 (a^{f (2)} . b^{f (4)} . c^{f (6)})}{a^{f (2)} + b^{f (4)} + c^{f (6)}}

C o

A l

[C o (C l) (e n)_{2}] C l

K_{3} [A l (C_{2} O_{4})_{3}]

Join BYJU'S Learning Program