The correct option is B Alkyl iodides on exposure to sunlight gradually darken
Tertiary alkyl halides undergo SN1 and not SN2 substitutions. It is because tertiary carbocations formed as an intermediate is stable(good for SN1) and also tertairy alkyl halides are sterically crowded, so it hinders attack of a nucleophile(not favourable for SN2).
Alkyl iodides on exposure to sunlight gradually darkens because the bond enthalpy of C−I is low and on exposure to sunlight, it breaks and free iodine start forming which show dark colour.
Alkyl fluorides do not give beilstein test positive.
Nucleophilic substitution is most frequent in alkyl iodides because of its low bond enthalpy.
Hence, (b) is correct.