Question

True masses of neutron,proton and deutron in $a.m.u$ are $1.00893,1.00813$ and $2.01473$ respectively. The packing fraction of the deutron in $a.m.u$ is

• A. $11.56\times {10}^{-4}$
• B. $23.5\times {10}^{-4}$
• C. $33.5\times {10}^{-4}$
• D. $47.15\times {10}^{-4}$

Answer 1

Answer: (A)

$11.56\times {10}^{-4}$

Deutron $={}_1^{2}H$ i.e., $1$ proton and $1$ neutron.

Packing fraction $=\frac{Truemass-Massnumber}{Massnumber}$

$=\frac{(1.00893+1.00813)-2.01473}{2.01473}$

$=11.56\times {10}^{-4}$