Truth table for the following digital circuit will be

\begin{matrix} x & y & z 0 & 0 & 1 0 & 1 & 1 1 & 0 & 1 1 & 1 & 1 \end{matrix}

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\begin{matrix} x & y & z 0 & 0 & 0 0 & 1 & 0 1 & 0 & 0 1 & 1 & 1 \end{matrix}

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\begin{matrix} x & y & z 0 & 0 & 0 0 & 1 & 1 1 & 0 & 1 1 & 1 & 1 \end{matrix}

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\begin{matrix} x & y & z 0 & 0 & 1 0 & 1 & 1 1 & 0 & 1 1 & 1 & 0 \end{matrix}

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Solution

The correct option is A $\begin{matrix} x & y & z 0 & 0 & 1 0 & 1 & 1 1 & 0 & 1 1 & 1 & 1 \end{matrix}$

Output, $z = ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ (x y) (¯ ¯ ¯ x y) = ¯ ¯¯¯¯ ¯ 0 y = ¯ ¯ ¯ 0 = 1 (∵ x ¯ ¯ ¯ x = 0 a n d y y = y)$
Whatever be the inputs to the given digital circuit, output will always be one.

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Similar questions

Q. Complete the following table to draw graph of the equations–
(I) x + y = 3 (II) x – y = 4

x + y = 3
x	3	$0$	$0$
y	$0$	5	3
(x, y)	(3, 0)	$0$	(0, 3)

x – y = 4
x	$0$	–1	0
y	0	$0$	–4
(x, y)	$0$	$0$	(0, –4)

The given truth table is for

$\begin{matrix} I n p u t & O u t p u t A ∣ B & Y 0 ∣ 0 & 1 0 ∣ 1 & 1 1 ∣ 0 & 1 1 ∣ 1 & 0 \end{matrix}$

Q. Complete the following table to draw the graph of 2x – 6y = 3

x	–5	$x$
y	$x$	0
(x, y)	$x$	$x$

Plot the point (x, y) given in the following table on the plane, choosing suitable units of distance on the axis.

x	− 2	− 1	0	1	3
y	8	7	−1.25	3	− 1

To plot the graphs of the following equations:
Equation 1: $3 x + 2 y = 1$
Equation 2: $y - 2 x = 2$
Fill in the values of p, q, r, and s in the given tables.
Equation 1:
$\begin{matrix} x & 0 & 5 y & p & q \end{matrix}$
Equation 2:
$\begin{matrix} x & r & s y & 0 & 5 \end{matrix}$

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Truth table for the following digital circuit will be

The correct option is A xyz001011101111 Output, z=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(xy)(¯¯¯xy)=¯¯¯¯¯¯0y=¯¯¯0=1(∵x¯¯¯x=0 and yy=y) Whatever be the inputs to the given digital circuit, output will always be one.