Question

Try to draw triangles with measurements as given below.

(i) AB = 5 cm, AC = 6 cm, ∠A = 60°

(ii) PQ = 4.5 cm, QR = 5 cm, ∠Q = 65°

(iii) XY = 7 cm, XZ = 5 cm, ∠X = 100°

(iv) CD = 5 cm, CE = 5 cm, ∠C = 40°

(v) LM = 4 cm, MN = 4 cm, ∠L = 60°

Answer 1

(i) The steps for construction of the required triangle are as follows.

1. Draw a line segment AB of length 5 cm.

2. Draw a line segment through point A, making an angle of 60° with AB.

3. Mark a point C at a distance of 6 cm from point A on the line segment drawn in the previous step.

4. Join BC.

Thus, ΔABC is the required triangle.

(ii) The steps for construction of the required triangle are as follows.

1. Draw a line segment PQ of length 4.5 cm.

2. Draw a line segment through the point Q, making an angle of 65° with PQ.

3. Mark a point R at a distance of 5 cm from Q on the line segment drawn in the previous step.

4. Join PR.

Thus, ΔPQR is the required triangle.

(iii) The steps for construction of the required triangle are as follows.

1. Draw a line segment XY of length 7 cm.

2. Draw a line segment through point X, making an angle of 100° with XY.

3. Mark a point Z at a distance of 5 cm from X on the line segment drawn in the previous step.

4. Join ZY.

Thus, ΔXYZ is the required triangle.

(iv) The steps for construction of the required triangle are as follows.

1. Draw a line segment CD of length 5 cm.

2. Draw a line through the point C, making an angle of 40° with CD.

3. Mark a point E at a distance of 5 cm from C on the line segment drawn in the previous step.

4. Join DE.

Thus, ΔCDE is the required triangle.

(v) The steps for construction oft the required triangle are as follows.

1. Draw a line segment LM of length 4 cm.

2. Draw a line segment through point L, making an angle of 60° with LM.

3. Draw part of a circle centred at M and of radius 4 cm on the line segment drawn in the previous step. Mark the point of intersection as N.

4. Join MN.

Thus, ΔLMN is the required triangle.