Question

Tungsten crystallizes in body centered cubic unit cell. If the edge of the cell unit cell is $316.5$pm, what is the radius of tungsten atom?

Answer 1

In a BCC $radius=\frac{edgelength}{2\surd 2}$
$radius=\frac{316.5}{2\surd 2}$
$=\frac{158.25}{1.414}$
$=111.91pm$
Therefore radius of tungsten atom is$111.91pm.$