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Question

Tuning fork A of frequency 258 Hz gives eight beats with a tuning fork B. When prongs of B are cut and again A and B are sounded, the number of beats heard remains the same. The frequency of B is?

A
242 Hz
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B
258 Hz
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C
264 Hz
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D
250 Hz
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Solution

The correct option is A 242 Hz
|FAFB|=8
|258FB|=8
FB=250/FB=266
When B prongs cut fπ equation increases so that means initially 2+ was = 250
So later become 266
So initially |258250|=8
so later |258266|=8
so fπ eq of B is = 250

1034177_1019854_ans_ba94043b318847828560f86f265d11ad.png

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