The correct option is A 300Hz
The phenomenon of beats is used in the determination of unknown frequencies.
Suppose v2 is the unknown frequency of a tuning fork B. Let this fork B produce m beats per second with another tuning fork A of known frequency v1.
As number of beats/s is equal to difference in frequency of two sources.
Therefore, v2=v1±m
When the prong of fork B is filled a little, it becomes lighter and its frequency of vibration increases on sounding the filed fork B with fork A, we count the number of beats/s.
Proceeding as, we conclude that, if number of beats/s on filing fork B of unknown frequency increases, m would be positive and vice-versa. So, frequency of tuning fork B=305±5=310Hz,300Hz
Since, on filling tuning fork B, number of beats decreases. This means that frequency of B should be less ie., 300Hz.