Question

Tuning fork A when sounded with a tuning fork B of frequency 480 Hz gives 5 beats per second. When the prongs of A are loaded with wax, it gives 3 beats per second. Find the original frequency of A.

Answer 1

Before loaded wax, $n=5$ beats per sec . Given $f_B=480$ Hz

so, $f_A=480+5=485$ Hz or $480-5=475$ Hz

On loading fork A its frequency decreases. But the beat decreases to 3 beats per sec.

So, $f_A$ is greater than $f_B$ . Thus, $f_A=485$ Hz