wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Tuning fork for A has frequency 1% greater than that of standard fork B while tuning fork C has frequency 2% smaller than that of B. When A and B are sounded together, then number of beats heard per second is 5. The frequency of tuning fork C is approximately

A
93Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
163Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
233Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
283Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 163Hz
If we consider the frequencies of the tuning forks A,B and C as n1,n2 and n3.
This means the frequency of n1=n2(1+.01)=1.01n2
n3=n2(10.02)=0.98n2
But, n1n3=5 and (1.01n20.98n2)=5
n2=166.7Hz (approx)
n3=0.98×166.7
n3=163Hz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Beats
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon