Turn-over number of the fastest enzyme is

18 \times 10^{4}

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10^{4}

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36 \times 10^{6}

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10^{5}

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Solution

The correct option is C $36 \times 10^{6}$
The number of substrate molecules converted into product per minute by enzymes is called as the turnover number. The higher the turn over number, the more efficient an enzyme. It depends upon all the active points present over enzymes. Enzymes carbonic anhydrase is 36 million turns over, enzymes present in RBC, 5 million of catalase etc. Thus, the correct answer is C.

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