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Question

Turnbull's blue is :

A
Fe3[Fe(CN)6]2
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B
K4Fe(CN)6
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C
K3Fe(CN)6
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D
Na4Fe(CN)6
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Solution

The correct option is A Fe3[Fe(CN)6]2
Turnbull's blue is Fe3[Fe(CN)6]2.
The structure is as follows:

166240_183446_ans_8000b0479fc54321beaa85d45a9823ac.png

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