Question

Turning is done using a tool of 5 - 5 - 8 - 8 - 8 - 25 - 0.1 mm, geometry, with a feed of 0.1 mm/stroke and depth of cut of 2 mm.

If shear angle is ${30}^{\circ }$, the plan area of cut in $m{m}^2$ is

• A. 0.4
• B. 0.3
• C. 0.2
• D. 0.1

Answer 1

The correct option is A 0.4

$\text{Plane area of cut}=\frac{\text{f.d}}{\sin \varphi }$
$=\frac{0.1\times 2}{\sin 30}=0.4{\text{mm}}^2$