Question

Twelve resistors each of resistance $1$ $\Omega$ are connected in the circuit shown in figure. Net resistance between point A and H would be.

• A. $\frac{5}{3}\Omega$
• B. $1\Omega$
• C. $\frac{3}{4}\Omega$
• D. $\frac{7}{6}\Omega$

Answer 1

The correct option is C $\frac{3}{4}\Omega$

Let current i enters from point A and leaves at H. Then current can be distributed as follows. From the figure we can see that no current will flow in wires CE and FD. So, the simple circuit is as follows.
$\therefore R_{AH}=\frac{3}{4}\Omega$.