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Question

Twelve wires, each having equal resistance of 2 Ω, are joined to form a cube. Equivalent resistance between the ends of a face diagonal is.


Correct Answer
A
1.5Ω
Your Answer
B
0.4Ω
Your Answer
C
0.66Ω
Your Answer
D
1.25Ω

Solution

The correct option is A 1.5Ω

Im going to take a current I flowing in through A due to an externally connected cell V. Let the current going into AC be i. That must be the same current coming through EB into node B because those two arms are symmetric. I’m just calling a junction a node. Now, Currents through arms AD and AH must be the same. Let it be (Ii)2. Now currents must divide at junction C symmetrically as i2 and i2. There must be no currents through the arms HF and DG as the currents are the same through AD and DB; and hence CF and FE.

Thus if there is a cell connected between A and B with voltage V,
Taking loop ABEA,
2(Ii)2+2(Ii)2V=0V=2(Ii)(1)Now take loop ACFEBA,2i+2i2+2i2+2iV=0V=6ii=V6Plugging this back into (1),V=2IV34V3=2IVI=32Ω
The resistance between points A and B is 32Ω.
 

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