This is a very simple question. Let M be the angle, the arc of the sector AOB makes with the center O. Let OA = OB = radius r.
Given OA + Arc AB + OB = 20 --> 2r + rM = 20 --> M = (20-2r)/r. ..... (1)
Area A of the sector = (M/2)rr = 10r-(r*r) ---------- From (1)
dA/dr = 10 - 2r = 0 ----> r=5
Second derivative is negative for r =5
We get maximum area at r=5
A = 25 ----------- From (1)
Answer :25m^2