Twice an integer is added to the square of the integer. Next, the result is increased by 1. Which of the following could be the value of the final sum?
A
36
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B
42
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C
45
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D
48
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E
50
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Solution
The correct option is A36 Let the integer is x. As per question, the calculation is 2x+x2+1=(x+1)2 Try plugging in some real numbers until you get one of the answers. As, x=1;(1+1)2=4 x=3;(3+1)2=16 x=5;(5+1)2=36 Hence,choice A is correct.