Twice of a number is added to four times of another number, then which of the following represents correct unchanging relation?

2 (x + y)

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2 (x + 2 y)

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4 (x + y)

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4 (x + 2 y)

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Solution

The correct option is B $2 (x + 2 y)$
Let first number be $^{'} x^{'}$ and second number be $^{'} y^{'}$ .
Since, it is given that twice of the first number is added to four times of second number. This statement can be written as:
$2 x + 4 y = 2 (x + 2 y)$
$∴$ $2 (x + 2 y)$ is the correct unchanging relation.

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Twice of a number is added to four times of another number, then which of the following represents correct unchanging relation?

The correct option is B 2(x+2y)Let first number be ′x′ and second number be ′y′. Since, it is given that twice of the first number is added to four times of second number. This statement can be written as: 2x+4y=2(x+2y) ∴ 2(x+2y) is the correct unchanging relation.