Question

Twice the difference (absolute) between the roots of $16x^2-24x=0$ is:

Answer 1

The given equation may be written as $8x(2x-3)=0$
This gives $x=0$ or $x=\frac{3}{2}$
$x=0,\frac{3}{2}$ are the required solutions

The absolute difference between the roots is $(\frac{3}{2}-0)=\frac{3}{2}$

$\therefore$ twice the difference will be $3$.