Two 2 H inductance coils are connected in series and are also magnetically coupled to each other. The coefficient of coupling being 0.1. The total inductance of the combination can be
A
0.4 H
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B
3.2 H
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C
4.0 H
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D
4.4 H
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Solution
The correct option is D 4.4 H L=L1+L2±2M =L1+L2±2k√L1L2 L=2+2±2(0.1)√2×2=4±0.4 L=3.6H and 4.4H