Two $220$ V, $100$ W bulbs are connected first in series and then in parallel. Each time the combination is connected to a $220$ V AC supply line, the power drawn by the combination in each case respectively will be :

50 W, 200 W

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50 W, 20 W

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100 W, 50 W

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200 W, 150 W

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Solution

The correct option is A $50 W, 200 W$
In series, power, $P = \frac{V^{2}}{2 R} = \frac{P}{2} = 50$ W
In parallel, power, $P = \frac{V^{2}}{R_{/ 2}} = 2 P = 200 W$ .

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Two 220V, 100W bulbs are connected first in series and then in parallel. Each time the combination is connected to a 220V AC supply line, the power drawn by the combination in each case respectively will be :

The correct option is A 50W,200WIn series, power, P=V22R=P2=50WIn parallel, power, P=V2R/2=2P=200W.

Two $220$ V, $100$ W bulbs are connected first in series and then in parallel. Each time the combination is connected to a $220$ V AC supply line, the power drawn by the combination in each case respectively will be :

The correct option is A $50 W, 200 W$
In series, power, $P = \frac{V^{2}}{2 R} = \frac{P}{2} = 50$ W
In parallel, power, $P = \frac{V^{2}}{R_{/ 2}} = 2 P = 200 W$ .